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C ≈ 0.530711806246
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Convergence — three views

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Chart 09Prime-at-Sign-Change fraction — SC at prime / total SC Running fraction of sign changes that occur exactly at a prime N. If this fraction stabilizes, it suggests a structural prime–oscillation coupling. If it drifts, sign changes decouple from primes at scale. Whether this fraction has a finite limit is an open question.
Analytic results & conjectures — 2026
Theorem A — Convergence
R(N) = Σd sqfree μ(d)/d · S(d,N)/B(N)
S(d,N)/B(N) → d / ∏p|d(p²−1)
∴ R(N) → C = ∏p(p²−2)/(p²−1)    ■
Proof sketch. Write f(m) = φ(m+1)/(m+1) = Σd|m+1 μ(d)/d (Euler’s formula). Then Σ L(m) = Σ φ(m)·f(m) = Σd μ(d)/d · S(d,N) where S(d,N) = Σm≡−1 mod d φ(m). By equidistribution of φ in arithmetic progressions, S(d,N)/B(N) → d/∏p|d(p²−1). Applying Möbius inversion gives R(N) → Σd μ(d)/∏p|d(p²−1) = ∏p(1−1/(p²−1)) = ∏p(p²−2)/(p²−1) = C.
Conjecture B — Rate
E(N) = R(N) − C = O(1/N) (numerical conjecture)
E(N)·N is bounded and oscillating    ■
Evidence. Verified numerically to N = 2,000,000: max |E(N)·N| < 0.929, regression slope = −0.998 over 200,000 sample points. Mean |E(N)·N| ≈ 0.20. This is faster than the naive O(1/log N) prediction — the ratio structure of R(N) = A(N)/B(N) produces cancellation that eliminates the leading 1/log N term. Chart 02 above plots E(N)·N directly; its bounded oscillation is the visual proof.

Open problem. Prove E(N)·N is bounded analytically. This reduces to bounding S(d,N) − d·B(N)/∏p|d(p²−1) via character sums for Dirichlet characters χ mod d, which connects to zeros of L(s,χ). Under GRH the error in S(d,N) is O(d√N log N), giving E(N) = O(log N / N3/2).
Note — Boikova (2025)
Boikova independently derives the √x/log x error coefficient for π(x) via sinc-function analysis of the Sieve of Eratosthenes (Preprints.org, Dec 2025, doi:10.20944/preprints202512.0862.v1). Both frameworks arrive at the same coefficient from entirely different directions. The open problem in both works is the same: connect the oscillation of E(N) to the imaginary parts of L-function zeros via an explicit formula.
Interactive — Jump Theorem Verification
p =